{"id":17966,"date":"2024-03-26T14:03:20","date_gmt":"2024-03-26T14:03:20","guid":{"rendered":"https:\/\/soicau5105.minhngocxoso.com\/?p=17966"},"modified":"2024-08-23T15:30:02","modified_gmt":"2024-08-23T08:30:02","slug":"tham-khao-nhung-meo-danh-xo-so-mien-bac-chuan","status":"publish","type":"post","link":"https:\/\/caulototheothu.com\/tham-khao-nhung-meo-danh-xo-so-mien-bac-chuan\/","title":{"rendered":"tham kh\u1ea3o nh\u1eefng m\u1eb9o \u0111\u00e1nh x\u1ed5 s\u1ed1 mi\u1ec1n b\u1eafc chu\u1ea9n"},"content":{"rendered":"\n
C\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc l\u00e0 nh\u1eefng c\u00e1ch t\u00ednh \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p t\u1eeb nhi\u1ec1u chuy\u00ean gia kinh nghi\u1ec7m l\u00e2u n\u0103m trong th\u1ecb tr\u01b0\u1eddng. C\u00e1ch \u0111\u00e1nh n\u00e0y \u0111ang ng\u01b0\u1eddi ch\u01a1i hi\u1ec7n nay \u00e1p d\u1ee5ng v\u00e0o soi c\u1ea7u m\u1ed7i ng\u00e0y v\u00e0 r\u1ea5t hi\u1ec7u qu\u1ea3. C\u00e1c ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ec1u c\u00f3 \u01b0u v\u00e0 nh\u01b0\u1ee3c \u0111i\u1ec3m kh\u00e1c nhau, ng\u01b0\u1eddi ch\u01a1i n\u00ean tham kh\u1ea3o nh\u1eefng m\u1eb9o b\u1eaft l\u00f4 \u0111\u1ec1 c\u0169ng nh\u01b0 c\u00e1c b\u00ed quy\u1ebft n\u00e0y v\u00e0 ch\u1ecdn ra cho m\u00ecnh nh\u1eefng c\u00e1ch \u0111\u00e1nh ph\u00f9 h\u1ee3p nh\u1ea5t.<\/p>\n\n\n\n
Gi\u1ea3i 7 x\u1ed5 s\u1ed1 MB c\u00f3 t\u1ea5t c\u1ea3 4 gi\u1ea3i, b\u1eaft c\u1ea7u gi\u1ea3i 7 l\u00e0 vi\u1ec7c b\u1ea1n gh\u00e9p c\u00e1c v\u1ecb tr\u00ed thu\u1ed9c 4 gi\u1ea3i n\u00e0y l\u1ea1i v\u1edbi nhau \u0111\u1ec3 t\u00ecm ra l\u00f4 t\u00f4, s\u1ed1 \u0111\u1ec1 \u0111\u1eb9p nh\u1ea5t. M\u1ed9t s\u1ed1 m\u1eb9o gh\u00e9p v\u1ecb tr\u00ed soi c\u1ea7u l\u00f4 gi\u1ea3i 7 chu\u1ea9n 100% nh\u01b0 sau:<\/p>\n\n\n\n
\u2013 Gh\u00e9p s\u1ed1 \u0111\u1ea7u gi\u1ea3i 7.1 v\u1edbi s\u1ed1 cu\u1ed1i gi\u1ea3i 7.4<\/p>\n\n\n\n
\u2013 Gh\u00e9p s\u1ed1 \u0111u\u00f4i gi\u1ea3i 7.1 v\u1edbi s\u1ed1 \u0111\u1ea7u gi\u1ea3i 7.4<\/p>\n\n\n\n
V\u1edbi c\u00e1ch n\u00e0y, b\u1ea1n s\u1ebd li\u1ec7t k\u00ea nh\u1eefng ch\u1eef s\u1ed1 thu\u1ed9c gi\u1ea3i 7 th\u00e0nh m\u1ed9t d\u00e3y s\u1ed1, sau \u0111\u00f3 gh\u00e9p l\u1ea7n l\u01b0\u1ee3t c\u00e1c s\u1ed1 trong d\u00e3y s\u1ed1 l\u1ea1i t\u1ea1o th\u00e0nh d\u00e0n \u0111\u1ec1 \u0111\u00e1nh ng\u00e0y h\u00f4m sau.<\/p>\n\n\n\n
V\u00ed d\u1ee5: Ng\u00e0y 01\/12\/2024, loto gi\u1ea3i 7 v\u1ec1 nh\u01b0 sau: 61, 90, 69, 18, t\u1ed5ng h\u1ee3p l\u1ea1i ta \u0111\u01b0\u1ee3c nh\u1eefng con s\u1ed1 0, 1, 6, 8, 9. K\u1ebft qu\u1ea3 ng\u00e0y 02\/12\/2024 l\u00f4 v\u1ec1: 01, 08, 89, 90, 96, 98.<\/p>\n\n\n\n
N\u1ebfu th\u1ea5y s\u1ed1 \u0111\u1ea7u ti\u00ean gi\u1ea3i 7.1 tr\u00f9ng v\u1edbi s\u1ed1 cu\u1ed1i gi\u1ea3i 7.4 h\u00f4m qua th\u00ec gh\u00e9p s\u1ed1 n\u00e0y v\u1edbi s\u1ed1 gi\u1eefa gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u00e1nh h\u00f4m nay.<\/p>\n\n\n\n
V\u00ed d\u1ee5: Gi\u1ea3i 7.1 l\u00e0 75, 7.4 l\u00e0 67, gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 12345. Gh\u00e9p 7 v\u1edbi 3 ta \u0111\u01b0\u1ee3c c\u1eb7p 37 \u2013 73.<\/p>\n\n\n\n
N\u1ebfu b\u1ea1n th\u1ea5y s\u1ed1 \u0111\u1ea7u gi\u1ea3i 7.1 tr\u00f9ng v\u1edbi s\u1ed1 cu\u1ed1i gi\u1ea3i 7.4 c\u00f3 th\u1ec3 gh\u00e9p s\u1ed1 n\u00e0y v\u1edbi s\u1ed1 gi\u1eefa gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau.<\/p>\n\n\n\n
C\u00f4ng th\u1ee9c t\u00ednh l\u00f4 \u0111\u1ec1 n\u00e0y nhi\u1ec1u cao th\u1ee7 trong c\u00e1c di\u1ec5n \u0111\u00e0n chia s\u1ebb v\u00e0 c\u0169ng c\u00f3 r\u1ea5t nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i kh\u00e1c \u00e1p d\u1ee5ng. C\u00e1c b\u01b0\u1edbc t\u00ednh nh\u01b0 sau:<\/p>\n\n\n\n
\u2013 L\u1ea5y s\u1ed1 \u0111\u1ec1 c\u1ee7a 2 ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3 ( DE v\u00e0 PQ) c\u1ed9ng theo c\u00f4ng th\u1ee9c:<\/p>\n\n\n\n
D + E + X = 10 (ho\u1eb7c 20)<\/p>\n\n\n\n
P + Q + Y = 20 (ho\u1eb7c 10)<\/p>\n\n\n\n
\u2013 T\u00ednh ra X, Y v\u00e0 \u0111\u00e1nh s\u1ed1 \u0111\u00f3 cho ng\u00e0y h\u00f4m nay. \u0110\u1ec3 ch\u1eafc \u0103n n\u00ean \u0111\u00e1nh song th\u1ee7 l\u00f4 XY \u2013 YX v\u00e0 c\u00f3 th\u1ec3 k\u1ebft h\u1ee3p b\u00f3ng s\u1ed1 l\u00f4 \u0111\u1ec1 c\u1ee7a c\u1eb7p s\u1ed1 n\u00e0y.<\/p>\n\n\n\n
V\u00ed d\u1ee5: \u0110\u1ec1 v\u1ec1 2 ng\u00e0y li\u00ean ti\u1ebfp l\u00e0 45, 83, d\u1ef1a theo c\u00f4ng th\u1ee9c ta c\u00f3:<\/p>\n\n\n\n
4 + 5 + X = 10, t\u00ednh \u0111\u01b0\u1ee3c X = 1<\/p>\n\n\n\n
8 + 3 + Y = 20, t\u00ednh \u0111\u01b0\u1ee3c Y = 9<\/p>\n\n\n\n
Nh\u01b0 v\u1eady, h\u00f4m nay b\u1ea1n \u0111\u00e1nh c\u1eb7p l\u00f4 19 \u2013 91.<\/p>\n\n\n\n
L\u00f4 \u0111\u1ea7u c\u00e2m t\u1ee9c l\u00e0 \u0111\u1ea7u c\u1ee7a con l\u00f4 \u0111\u00f3 kh\u00f4ng xu\u1ea5t hi\u1ec7n trong b\u1ea3ng k\u1ebft qu\u1ea3 ng\u00e0y h\u00f4m \u0111\u00f3. Ch\u00ednh v\u00ec s\u1ef1 \u0111\u1eb7c bi\u1ec7t nh\u01b0 v\u1eady n\u00ean nhi\u1ec1u ng\u01b0\u1eddi \u0111\u00e3 t\u00ecm ra quy lu\u1eadt \u0111\u00e1nh l\u00f4 theo \u0111\u1ea7u c\u00e2m l\u00e0 n\u1ebfu th\u1ea5y \u0111\u1ea7u l\u00f4 X c\u00e2m th\u00ec c\u00f3 th\u1ec3 \u0111\u00e1nh l\u00f4 0X \u2013 X0 \u2013 XX cho h\u00f4m sau.<\/p>\n\n\n\n
T\u01b0\u01a1ng t\u1ef1 nh\u01b0 l\u00f4 c\u00e2m \u0111\u1ea7u, b\u1eaft l\u00f4 c\u00e2m \u0111\u00edt c\u0169ng \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c nh\u01b0 v\u1eady v\u00e0 th\u01b0\u1eddng thi\u00ean v\u1ec1 \u0111\u00e1nh l\u00f4 k\u00e9p cho h\u00f4m sau. B\u1ea1n c\u00f3 th\u1ec3 t\u00ecm hi\u1ec3u th\u00eam v\u1ec1 c\u00e1ch b\u1eaft l\u00f4 theo \u0111\u1ea7u c\u00e2m, \u0111u\u00f4i c\u00e2m chi ti\u1ebft t\u1ea1i: Khi \u0111\u1ea7u \u0111\u00edt l\u00f4 c\u00e2m \u0111\u00e1nh con g\u00ec d\u1ec5 tr\u00fang nh\u1ea5t?<\/p>\n\n\n\n